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1、1根據(jù)立體圖作出三面投影,大小量取Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.5,6根據(jù)A點(diǎn)的坐標(biāo),作出三面投影和立體圖a’’XYZAVHWaa’Oaa’a’’根據(jù)長對(duì)正,寬相等,高平齊ZXYY長寬高Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011Aspos
2、ePtyLtd.aba’b’c’c’’d’d’’a’’b’’cdEvaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.9作出直線AB的側(cè)面投影,畫立體圖’XYZOVWHaa’bb’a’’b’’ABEvaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd
3、.10求直線AB的實(shí)長,及對(duì)兩投影面的傾角α,β做法提示:求α在水平投影上作,一直角邊是水平投影,另一直角邊為高度差。b’aba’α實(shí)長β實(shí)長求β在正面投影上,一直角邊是水正面投影,另一直角邊為寬度差。寬度差高度差Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.11已知直線AB的實(shí)際長度為55mm,求水平投影ab’a’高度差55mm水平投影b水平投影Evaluationonly.Crea
4、tedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.12判別下列各直線的空間位置,并注明反映實(shí)際長度的投影a’bb’acdc’d’fee’f’gg’h’(h)直線ABCDEFGH空間位置水平線側(cè)平線正平線鉛垂線實(shí)長投影abc’’d’’e’f’g’h’Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011As
5、posePtyLtd.13判別CDE三點(diǎn)是否在直線AB上e’a’bb’acc’dd’eC點(diǎn)不在;D點(diǎn)不在;E點(diǎn)在。Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.14應(yīng)用定比性補(bǔ)出直線AB上K點(diǎn)的水平投影,并完成側(cè)面投影aba’b’k’ka’’k’’b’’Evaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0
6、.0.Copyright2004-2011AsposePtyLtd.15求直線AB與投影面的交點(diǎn)n’baa’b’mm’nn’aba’b’nEvaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.16判別直線AB與CD,IJ與KL,MN與OP,QR與ST的相對(duì)位置AB與CD交錯(cuò),IJ與KL相交,MN與OP相交,QR與ST交錯(cuò)abcda’c’b’d’j’ikjli’k’l’p’mnm’n’opo’E
7、valuationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.17過A點(diǎn)作一直線平行于H面,并與BC直線相交a’bb’cc’ad’dEvaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011AsposePtyLtd.18過C點(diǎn)作一直線與AB相交,使交點(diǎn)離V面為20mmd’aa’bb’cc
8、’20mmdEvaluationonly.CreatedwithAspose.Slidesfor.NET3.5ClientProfile5.2.0.0.Copyright2004-2011As